Today we continued our investigation into optimizing rectangles and found:

With the same perimeter, we get a maximum area when the rectangle is square!

With the same area, we get a minimum perimeter when the rectangle is square!

We learned how to quickly find the dimensions of a square given the perimeter/area:

With a perimeter of 200 ft, you divide into 4 equal sides...200/4 = 50 ft by 50 ft.

With an area of 400 m^2, you square root...sqrt(400) = 20 m by 20 m.

Homework for next day is on page 431 (check overview for questions) and to also check out Khan Academy (link on the home page).

With the same perimeter, we get a maximum area when the rectangle is square!

With the same area, we get a minimum perimeter when the rectangle is square!

We learned how to quickly find the dimensions of a square given the perimeter/area:

With a perimeter of 200 ft, you divide into 4 equal sides...200/4 = 50 ft by 50 ft.

With an area of 400 m^2, you square root...sqrt(400) = 20 m by 20 m.

Homework for next day is on page 431 (check overview for questions) and to also check out Khan Academy (link on the home page).